Tenglamani yeching: (409 – 411):

 

409.      1) x2 – 12 = 0;                                2) x2 – 50 = 0;

3)                                4)

 

410.      1) x2 + 4x – 45 = 0;                         2) x2 – 9x – 52 = 0;

3) 3x2 – 7x – 40 = 0;                       4) 5x2 + 17x – 126 = 0.

 

411.      1) 4x2 – 2x – 3 = 0;                         2) 9x2 – 3x – 4 = 0;

3) 4x2 – 8x – 1 = 0;                         4) 3x2 + 4x – 1 = 0.

 

412.      Tenglamani yechmasdan, u nechta haqiqiy ildizga ega ekanini aniqlang:

1) x2 – 5x + 6 = 0;                          2) 5x2 + 7x – 8 = 0;

3) 25x2 – 10x + 1 = 0;                     4) 9x2 + 4x – 40 = 0.

 

413.      Kvadrat uchhadni ko`paytuvchilarga ajrating:

1) x2 + 12x +3 0;                             2) x2 – 10x + 16;

3) 2x2 + x – 1;                                4) 2x2 – 3x – 2.

 

414.      Kasrni qisqartiring:

1) ;                                       2)

3)                             4)

 

Tenglamani yeching: (415 – 416):

415.      1) x4 – 9x2 + 20 = 0;                       2) x4 – 11x2 + 18 = 0;

3) 2x4 – 5x2 + 2 = 0;                       4) 5x4 – 16x2 + 3 = 0.

416.      1)                          2)

3)               4)

 

417.      Yig`indisi 3 ga, kvadratlarining yig`indisi esa 5 ga teng bo`lgan ikkita son toping.

 

418.      Ayirmasi 1 ga, kvadratlarining yig`indisi esa  gat eng bo`lgan ikkita son toping.

 

419.      To`g`ri to`rburchakning bir tomoni ikkinchisidan 5 m ortiq, uning yuzi esa 84 m2 ga teng. To`g`ri to`rtburchakning tomonlarini toping.

 

420.      To`g`ri to`rtburchakning yuzi 675 sm2 ga teng. Agar to`g`ri to`rtburchak tomonlaridan biri ikkinchisidan 30 sm kichik bo`lsa, uning tomonlarini toping.

 

421.      Mi-6 vertolyotining havoga nisbatan tezligi 300 km/soat. U 224 km masofani ikki marta uchib o`tdi: birinchi marta shamol yo`nalishi bo`yicha, ikkinchi marta shamol yo`nalishiga qarshi. Agar vertolyot shamolga qarshi uchganda shamol yo`nalishi bo`yicha uchgandagiga qaraganda 6 min ko`p vaqt sarflagan bo`lsa, shamolning tezligini aniqlang.

 

422.      Velosipedchining yo`lning birinchi yarmidagi tezligiuning ikkinchi yarmidagi tezligidan 3 km/soat ortiq bo`ldi. Agar vilosipedchi 90 km li barcha yo`lni 5,5 soatda bosib o`tgan bo`lsa, u yo`lning ikkinchi yarmini qanday tezlik bilan bosob o`tgan?

 

423.      Daraxt o`tqazishda ikki guruh ishladi. Birinchi guruh har kuni ikkinchisiga qaraganda 400 tup ortiq daraxt o`tqazib, hammasi bo`lib 2700 tup daraxt o`tqazdi. Ikkinchi guruh 2 kun ortiq ishladi va 2500 tup daraxt o`tqazdi. Har bir guruh daraxt o`tqazishda necha kundan ishlagan?

 

424.      Tenglamalar sistemasini yeching:

1)                 2)                 3)

4)               5)             6)

7)            8)

 

O`ZINGIZNI TEKSHIRIB KO`RING!

1.           Tenglamni yeching:

1) 3x2 = 0;                             2) (x + 1)(x – 1) = 0;

3) 4x2 – 1 = 0;                       4) 3x2 = 5 x;

5) 4x2 – 4x + 1 = 0;              6) x2 – 16x – 17 =0;

7) 0,3x2 + 5x = 2;                 8) x2 – 4x + 5 = 0.

 

2.           Ko`paytuvchilarga ajrating:

 1)  x2 + x – 6;                       2) 2x2 – x – 3.

3.           Masalani yeching:

Qishloqlar orasidagi 36 km masofani bir velosipedchi ikkinchisidan 1 soat tezroq bosib o`tdi. Agar velosipedchilardan birining tezligi ikkinchisidan 3 km/soat ortiq ekani ma’lum bo`lsa, har bir velosipedchining tezligini toping.

 

4.           Tenglamalar sistemasini yeching:

 

 

Tenglamani yeching (425 – 427):

 

425.      1) 3x(x – 2) = x – 4;              2)

 

426.      1) 2x(x – 2) = (x + 1)2 – 9;     2) 5x(x – 4) = (x – 8)2 – 65;

3)           4)

 

427.      1) (x – 5)(x – 6) = 30;            2) (x + 2)(x + 3) = 6;

3) (x – 1)(x – 4) = 3x;            4) (x – 2)(x + 8) = 6x.

 

428.      x ning qanday qiymatlarida x2 + 3x – 88 ifodaning qiymati: 1) 0 ga; 2) 20 ga; 3) –18 ga; 4) –70 ga teng bo`ladi?

 

429.      Agar:

1) a = 3, b = 1, c = –4;                   2) a = 5, b = 2, c = 3;

3) a = 25, b = –10, c = 1;      4) a = 1, b = 0, c = –25

bo`lsa, ax2 + bx + c = 0 kvadrat tenglama nechta haqiqiy ildizga ega bo`ladi?

 

430.      Tenglamani yeching:

1)

2) .

 

431.      Ustaxona ma’lum muddatda 5400 juft poyabzal tayyorlashi kerak. Aslida u kuniga mo`ljallanganidan 30 juft ortiq mahsulot tayyorladi va buyurtmani muddatidan 9 kun oldin bajardi. Buyurtma necha kunda bajarilgan?

 

432.      Ikki sayyoh velosipedlarida A qishloqdan B qishloqqa qarab har xil yo`ldan jo`nadi. Birinchisi 30 km, ikkinchisi esa 20 km yurishi kerak edi. Birinchi sayyohning tezligi ikkinchisinikidan 3km/soat ortiq. Biroq ikkinchi sayyoh B ga birinchisiga qaraganda 20 min oldin yetib keldi. Har bir sayyoh yo`lda qancha vaqt bo`lgan?

 

433.      Ishchilarning ikki guruhi yo`lni ta’mirlashni 4 soatda tugatdilar. Agar avval birinchi guruh yo`lning yarmini, so`ngra esa ikkinchisi qolgan qismini ta’mirlaganida edi, barcha ta’mirlash ishlari 9 soatda tugallangan bo`lar edi. Yo`lni har bir guruh alohida-alohida qancha vaqtda ta’mirlaydi?

 

434.      Tenglamalar sistemani yeching:

1)                                2)

3)                         4)

 

435.      x1 = –3 qiymat 5x2 + 12x + q = 0 tenglamaning ildizi bo`lsin. x2 ni toping.